(9x-2)+(9x-2)=(10x+18)

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Solution for (9x-2)+(9x-2)=(10x+18) equation: 



(9x-2)+(9x-2)=(10x+18)

We move all terms to the left:

(9x-2)+(9x-2)-((10x+18))=0

We get rid of parentheses

9x+9x-((10x+18))-2-2=0



We calculate terms in parentheses: -((10x+18)), so:

(10x+18)

We get rid of parentheses

10x+18

Back to the equation:

-(10x+18)



We add all the numbers together, and all the variables

18x-(10x+18)-4=0

We get rid of parentheses

18x-10x-18-4=0

We add all the numbers together, and all the variables

8x-22=0

We move all terms containing x to the left, all other terms to the right

8x=22

x=22/8

x=2+3/4

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