(9x-2)+(5x+20)=(4x+36)

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Solution for (9x-2)+(5x+20)=(4x+36) equation: 



(9x-2)+(5x+20)=(4x+36)

We move all terms to the left:

(9x-2)+(5x+20)-((4x+36))=0

We get rid of parentheses

9x+5x-((4x+36))-2+20=0



We calculate terms in parentheses: -((4x+36)), so:

(4x+36)

We get rid of parentheses

4x+36

Back to the equation:

-(4x+36)



We add all the numbers together, and all the variables

14x-(4x+36)+18=0

We get rid of parentheses

14x-4x-36+18=0

We add all the numbers together, and all the variables

10x-18=0

We move all terms containing x to the left, all other terms to the right

10x=18

x=18/10

x=1+4/5

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