(9x-2)+(3x-19)+(3x+6)=180

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Solution for (9x-2)+(3x-19)+(3x+6)=180 equation: 



(9x-2)+(3x-19)+(3x+6)=180

We move all terms to the left:

(9x-2)+(3x-19)+(3x+6)-(180)=0

We get rid of parentheses

9x+3x+3x-2-19+6-180=0

We add all the numbers together, and all the variables

15x-195=0

We move all terms containing x to the left, all other terms to the right

15x=195

x=195/15

x=13

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