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(9x-2)(x+9)=0
We multiply parentheses ..
(+9x^2+81x-2x-18)=0
We get rid of parentheses
9x^2+81x-2x-18=0
We add all the numbers together, and all the variables
9x^2+79x-18=0
a = 9; b = 79; c = -18;
Δ = b2-4ac
Δ = 792-4·9·(-18)
Δ = 6889
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6889}=83$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(79)-83}{2*9}=\frac{-162}{18} =-9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(79)+83}{2*9}=\frac{4}{18} =2/9 $
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