(9x-1)-(1-4x)=(2x+8)+2*(9x+16)

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Solution for (9x-1)-(1-4x)=(2x+8)+2*(9x+16) equation: 



(9x-1)-(1-4x)=(2x+8)+2(9x+16)

We move all terms to the left:

(9x-1)-(1-4x)-((2x+8)+2(9x+16))=0

We add all the numbers together, and all the variables

(9x-1)-(-4x+1)-((2x+8)+2(9x+16))=0

We get rid of parentheses

9x+4x-((2x+8)+2(9x+16))-1-1=0



We calculate terms in parentheses: -((2x+8)+2(9x+16)), so:

(2x+8)+2(9x+16)

We multiply parentheses

(2x+8)+18x+32

We get rid of parentheses

2x+18x+8+32

We add all the numbers together, and all the variables

20x+40

Back to the equation:

-(20x+40)



We add all the numbers together, and all the variables

13x-(20x+40)-2=0

We get rid of parentheses

13x-20x-40-2=0

We add all the numbers together, and all the variables

-7x-42=0

We move all terms containing x to the left, all other terms to the right

-7x=42

x=42/-7

x=-6

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