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(9x+9)(12x-3)=180
We move all terms to the left:
(9x+9)(12x-3)-(180)=0
We multiply parentheses ..
(+108x^2-27x+108x-27)-180=0
We get rid of parentheses
108x^2-27x+108x-27-180=0
We add all the numbers together, and all the variables
108x^2+81x-207=0
a = 108; b = 81; c = -207;
Δ = b2-4ac
Δ = 812-4·108·(-207)
Δ = 95985
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{95985}=\sqrt{81*1185}=\sqrt{81}*\sqrt{1185}=9\sqrt{1185}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(81)-9\sqrt{1185}}{2*108}=\frac{-81-9\sqrt{1185}}{216} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(81)+9\sqrt{1185}}{2*108}=\frac{-81+9\sqrt{1185}}{216} $
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