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(9x+41)=(33+x)
We move all terms to the left:
(9x+41)-((33+x))=0
We add all the numbers together, and all the variables
(9x+41)-((x+33))=0
We get rid of parentheses
9x-((x+33))+41=0
We calculate terms in parentheses: -((x+33)), so:We get rid of parentheses
(x+33)
We get rid of parentheses
x+33
Back to the equation:
-(x+33)
9x-x-33+41=0
We add all the numbers together, and all the variables
8x+8=0
We move all terms containing x to the left, all other terms to the right
8x=-8
x=-8/8
x=-1
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