(9x+3)/2x-1=(2x-1)/11-x

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Solution for (9x+3)/2x-1=(2x-1)/11-x equation: 



(9x+3)/2x-1=(2x-1)/11-x

We move all terms to the left:

(9x+3)/2x-1-((2x-1)/11-x)=0



Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R





Domain of the equation: 11-x)!=0

We move all terms containing x to the left, all other terms to the right

-x)!=-11

x!=-11/1

x!=-11

x∈R



We calculate fractions


(99x-x)+33)/(22x-x))+(-((2x-1)*2x)/(22x-x))-1=0

We add all the numbers together, and all the variables

(+98x)+21x))+(-((2x-1)*2x)/(+21x))-1+33)/(=0

We get rid of parentheses

98x+21x))+(-((2x-1)*2x)/(+21x))-1+33)/(=0

We multiply all the terms by the denominator


98x*(+21x))+(-((2x-1)*2x)+21x))-1+33)=0



We calculate terms in parentheses: -((2x-1)*2x), so:

(2x-1)*2x

We multiply parentheses

4x^2-2x

Back to the equation:

-(4x^2-2x)



We get rid of parentheses

-4x^2+98x*(+21x))+(+2x+21x))-1+33)=0

We add all the numbers together, and all the variables

-4x^2+98x*(+21x))+(+23x))-1+33)=0

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