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(9x+3)+(11x-21)=(5x-2)
We move all terms to the left:
(9x+3)+(11x-21)-((5x-2))=0
We get rid of parentheses
9x+11x-((5x-2))+3-21=0
We calculate terms in parentheses: -((5x-2)), so:We add all the numbers together, and all the variables
(5x-2)
We get rid of parentheses
5x-2
Back to the equation:
-(5x-2)
20x-(5x-2)-18=0
We get rid of parentheses
20x-5x+2-18=0
We add all the numbers together, and all the variables
15x-16=0
We move all terms containing x to the left, all other terms to the right
15x=16
x=16/15
x=1+1/15
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