(9x+29)+(93-5x)+(10x-2)=180

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Solution for (9x+29)+(93-5x)+(10x-2)=180 equation:



(9x+29)+(93-5x)+(10x-2)=180
We move all terms to the left:
(9x+29)+(93-5x)+(10x-2)-(180)=0
We add all the numbers together, and all the variables
(9x+29)+(-5x+93)+(10x-2)-180=0
We get rid of parentheses
9x-5x+10x+29+93-2-180=0
We add all the numbers together, and all the variables
14x-60=0
We move all terms containing x to the left, all other terms to the right
14x=60
x=60/14
x=4+2/7

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