(9x+29)+(93-5x)+(10x+2)+90=180

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Solution for (9x+29)+(93-5x)+(10x+2)+90=180 equation: 



(9x+29)+(93-5x)+(10x+2)+90=180

We move all terms to the left:

(9x+29)+(93-5x)+(10x+2)+90-(180)=0

We add all the numbers together, and all the variables

(9x+29)+(-5x+93)+(10x+2)+90-180=0

We add all the numbers together, and all the variables

(9x+29)+(-5x+93)+(10x+2)-90=0

We get rid of parentheses

9x-5x+10x+29+93+2-90=0

We add all the numbers together, and all the variables

14x+34=0

We move all terms containing x to the left, all other terms to the right

14x=-34

x=-34/14

x=-2+3/7

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