(9x+28)+(3x+38)=90

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Solution for (9x+28)+(3x+38)=90 equation: 



(9x+28)+(3x+38)=90

We move all terms to the left:

(9x+28)+(3x+38)-(90)=0

We get rid of parentheses

9x+3x+28+38-90=0

We add all the numbers together, and all the variables

12x-24=0

We move all terms containing x to the left, all other terms to the right

12x=24

x=24/12

x=2

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