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(9x+10)/(-3x+1)=x
We move all terms to the left:
(9x+10)/(-3x+1)-(x)=0
Domain of the equation: (-3x+1)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
-3x!=-1
x!=-1/-3
x!=1/3
x∈R
-1x+(9x+10)/(-3x+1)=0
We multiply all the terms by the denominator
-1x*(-3x+1)+(9x+10)=0
We multiply parentheses
3x^2-x+(9x+10)=0
We get rid of parentheses
3x^2-x+9x+10=0
We add all the numbers together, and all the variables
3x^2+8x+10=0
a = 3; b = 8; c = +10;
Δ = b2-4ac
Δ = 82-4·3·10
Δ = -56
Delta is less than zero, so there is no solution for the equation
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