(9x+1)(x+2)=(3x+2)(3x-4)

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Solution for (9x+1)(x+2)=(3x+2)(3x-4) equation: 



(9x+1)(x+2)=(3x+2)(3x-4)

We move all terms to the left:

(9x+1)(x+2)-((3x+2)(3x-4))=0

We multiply parentheses ..

(+9x^2+18x+x+2)-((3x+2)(3x-4))=0



We calculate terms in parentheses: -((3x+2)(3x-4)), so:

(3x+2)(3x-4)

We multiply parentheses ..

(+9x^2-12x+6x-8)

We get rid of parentheses

9x^2-12x+6x-8

We add all the numbers together, and all the variables

9x^2-6x-8

Back to the equation:

-(9x^2-6x-8)



We get rid of parentheses

9x^2-9x^2+18x+x+6x+2+8=0

We add all the numbers together, and all the variables

25x+10=0

We move all terms containing x to the left, all other terms to the right

25x=-10

x=-10/25

x=-2/5

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