(9t-7)(t+6)=(3t+5)(3t-4)

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Solution for (9t-7)(t+6)=(3t+5)(3t-4) equation: 



(9t-7)(t+6)=(3t+5)(3t-4)

We move all terms to the left:

(9t-7)(t+6)-((3t+5)(3t-4))=0

We multiply parentheses ..

(+9t^2+54t-7t-42)-((3t+5)(3t-4))=0



We calculate terms in parentheses: -((3t+5)(3t-4)), so:

(3t+5)(3t-4)

We multiply parentheses ..

(+9t^2-12t+15t-20)

We get rid of parentheses

9t^2-12t+15t-20

We add all the numbers together, and all the variables

9t^2+3t-20

Back to the equation:

-(9t^2+3t-20)



We get rid of parentheses

9t^2-9t^2+54t-7t-3t-42+20=0

We add all the numbers together, and all the variables

44t-22=0

We move all terms containing t to the left, all other terms to the right

44t=22

t=22/44

t=1/2

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