(9p+4)(2p-3)=0

Solution for (9p+4)(2p-3)=0 equation:

(9p+4)(2p-3)=0

We multiply parentheses ..

(+18p^2-27p+8p-12)=0

We get rid of parentheses

18p^2-27p+8p-12=0

We add all the numbers together, and all the variables

18p^2-19p-12=0

a = 18; b = -19; c = -12;
Δ = b2-4ac
Δ = -192-4·18·(-12)
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-35}{2*18}=\frac{-16}{36}
=-4/9
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+35}{2*18}=\frac{54}{36}
=1+1/2
$