(9b-14)+3b=4(b+5)-10

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Solution for (9b-14)+3b=4(b+5)-10 equation: 



(9b-14)+3b=4(b+5)-10

We move all terms to the left:

(9b-14)+3b-(4(b+5)-10)=0

We add all the numbers together, and all the variables

3b+(9b-14)-(4(b+5)-10)=0

We get rid of parentheses

3b+9b-(4(b+5)-10)-14=0



We calculate terms in parentheses: -(4(b+5)-10), so:

4(b+5)-10

We multiply parentheses

4b+20-10

We add all the numbers together, and all the variables

4b+10

Back to the equation:

-(4b+10)



We add all the numbers together, and all the variables

12b-(4b+10)-14=0

We get rid of parentheses

12b-4b-10-14=0

We add all the numbers together, and all the variables

8b-24=0

We move all terms containing b to the left, all other terms to the right

8b=24

b=24/8

b=3

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