(9a+b)/6=(-6a+7c)/-5

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Solution for (9a+b)/6=(-6a+7c)/-5 equation: 


x in (-oo:+oo)

(9*a+b)/6 = (7*c-6*a)/(-5) // - (7*c-6*a)/(-5)

(9*a+b)/6-((7*c-6*a)/(-5)) = 0

(9*a+b)/6+(-1*(7*c-6*a))/(-5) = 0

(-5*(9*a+b))/(-5*6)+(-1*6*(7*c-6*a))/(-5*6) = 0

-5*(9*a+b)-1*6*(7*c-6*a) = 0

-9*a-5*b-42*c = 0

(-9*a-5*b-42*c)/(-5*6) = 0

(-9*a-5*b-42*c)/(-5*6) = 0 // * -5*6

-9*a-5*b-42*c = 0

x belongs to the empty set

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