(92/6x)=-(1/12)

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Solution for (92/6x)=-(1/12) equation: 



(92/6x)=-(1/12)

We move all terms to the left:

(92/6x)-(-(1/12))=0



Domain of the equation: 6x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+92/6x)-(-(+1/12))=0

We get rid of parentheses

92/6x-(-(+1/12))=0

We calculate fractions


()/72x^2+(-(-(+1*6x)/72x^2=0

We multiply all the terms by the denominator


(-(-(+1*6x)+()=0



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