(9/x)+(4/2x)=-10

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Solution for (9/x)+(4/2x)=-10 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

(4/2)*x+9/x = -10 // + 10

(4/2)*x+9/x+10 = 0

2*x^1+9*x^-1+10*x^0 = 0

(2*x^2+10*x^1+9*x^0)/(x^1) = 0 // * x^2

x^1*(2*x^2+10*x^1+9*x^0) = 0

x^1

2*x^2+10*x+9 = 0

2*x^2+10*x+9 = 0

DELTA = 10^2-(2*4*9)

DELTA = 28

DELTA > 0

x = (28^(1/2)-10)/(2*2) or x = (-28^(1/2)-10)/(2*2)

x = (2*7^(1/2)-10)/4 or x = (-2*7^(1/2)-10)/4

x in { (-2*7^(1/2)-10)/4, (2*7^(1/2)-10)/4} 

x in { (-2*7^(1/2)-10)/4, (2*7^(1/2)-10)/4 }

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