(9-3x)/(4x-12)=3

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Solution for (9-3x)/(4x-12)=3 equation: 


D( x )

4*x-12 = 0

4*x-12 = 0

4*x-12 = 0

4*x-12 = 0 // + 12

4*x = 12 // : 4

x = 12/4

x = 3

x in (-oo:3) U (3:+oo)

(9-(3*x))/(4*x-12) = 3 // - 3

(9-(3*x))/(4*x-12)-3 = 0

(9-3*x)/(4*x-12)-3 = 0

(9-3*x)/(4*x-12)+(-3*(4*x-12))/(4*x-12) = 0

9-3*(4*x-12)-3*x = 0

45-15*x = 0

(45-15*x)/(4*x-12) = 0

(45-15*x)/(4*x-12) = 0 // * 4*x-12

45-15*x = 0

45-15*x = 0 // - 45

-15*x = -45 // : -15

x = -45/(-15)

x = 3

x in { 3} 

x belongs to the empty set

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