(9-2y)/4)+(y+2)/2)=6

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Solution for (9-2y)/4)+(y+2)/2)=6 equation: 



(9-2y)/4)+(y+2)/2)=6

We move all terms to the left:

(9-2y)/4)+(y+2)/2)-(6)=0



Domain of the equation: 4)+(y!=0

y∈R



We add all the numbers together, and all the variables

(-2y+9)/4)+(y+2)/2)-6=0

We add all the numbers together, and all the variables

(-2y+9)/4)+(y+1=0

We multiply all the terms by the denominator


(-2y+9)+1*4)+(y=0

Wy multiply elements

(-2y+9)+4y=0

We get rid of parentheses

-2y+4y+9=0

We add all the numbers together, and all the variables

2y+9=0

We move all terms containing y to the left, all other terms to the right

2y=-9

y=-9/2

y=-4+1/2

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