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(9+u)(4u-2)=0
We add all the numbers together, and all the variables
(u+9)(4u-2)=0
We multiply parentheses ..
(+4u^2-2u+36u-18)=0
We get rid of parentheses
4u^2-2u+36u-18=0
We add all the numbers together, and all the variables
4u^2+34u-18=0
a = 4; b = 34; c = -18;
Δ = b2-4ac
Δ = 342-4·4·(-18)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1444}=38$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-38}{2*4}=\frac{-72}{8} =-9 $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+38}{2*4}=\frac{4}{8} =1/2 $
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