(9+h)h=56

Solution for (9+h)h=56 equation:

(9+h)h=56

We move all terms to the left:

(9+h)h-(56)=0

We add all the numbers together, and all the variables

(h+9)h-56=0

We multiply parentheses

h^2+9h-56=0

a = 1; b = 9; c = -56;
Δ = b2-4ac
Δ = 92-4·1·(-56)
Δ = 305
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{305}}{2*1}=\frac{-9-\sqrt{305}}{2}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{305}}{2*1}=\frac{-9+\sqrt{305}}{2}
$