(9+2x)(6+2x)=0

Solution for (9+2x)(6+2x)=0 equation:

(9+2x)(6+2x)=0

We add all the numbers together, and all the variables

(2x+9)(2x+6)=0

We multiply parentheses ..

(+4x^2+12x+18x+54)=0

We get rid of parentheses

4x^2+12x+18x+54=0

We add all the numbers together, and all the variables

4x^2+30x+54=0

a = 4; b = 30; c = +54;
Δ = b2-4ac
Δ = 302-4·4·54
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-6}{2*4}=\frac{-36}{8}
=-4+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+6}{2*4}=\frac{-24}{8}
=-3
$