(8y/y-10)+6=(2y/y-10)

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Solution for (8y/y-10)+6=(2y/y-10) equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

(8*y)/y-10+6 = (2*y)/y-10 // - (2*y)/y-10

(8*y)/y-((2*y)/y)-10+6+10 = 0

(8*y)/y-10-2+6+10 = 0

12 = 0

y belongs to the empty set

y belongs to the empty set

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