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(8y-12)(1.2+0.3y)=0
We add all the numbers together, and all the variables
(8y-12)(0.3y+1.2)=0
We multiply parentheses ..
(+0y^2+9.6y+0y-14.4)=0
We get rid of parentheses
0y^2+9.6y+0y-14.4=0
We add all the numbers together, and all the variables
y^2+10.6y-14.4=0
a = 1; b = 10.6; c = -14.4;
Δ = b2-4ac
Δ = 10.62-4·1·(-14.4)
Δ = 169.96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10.6)-\sqrt{169.96}}{2*1}=\frac{-10.6-\sqrt{169.96}}{2} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10.6)+\sqrt{169.96}}{2*1}=\frac{-10.6+\sqrt{169.96}}{2} $
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