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(8y+4)+(4y=3)=
We move all terms to the left:
(8y+4)+(4y-(3))=0
We get rid of parentheses
8y+4y+4-3=0
We add all the numbers together, and all the variables
12y+1=0
We move all terms containing y to the left, all other terms to the right
12y=-1
y=-1/12
y=-1/12
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