(8y+4)(4y+8)=(15y-9)

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Solution for (8y+4)(4y+8)=(15y-9) equation: 



(8y+4)(4y+8)=(15y-9)

We move all terms to the left:

(8y+4)(4y+8)-((15y-9))=0

We multiply parentheses ..

(+32y^2+64y+16y+32)-((15y-9))=0



We calculate terms in parentheses: -((15y-9)), so:

(15y-9)

We get rid of parentheses

15y-9

Back to the equation:

-(15y-9)



We get rid of parentheses

32y^2+64y+16y-15y+32+9=0

We add all the numbers together, and all the variables

32y^2+65y+41=0

a = 32; b = 65; c = +41;
Δ = b2-4ac
Δ = 652-4·32·41
Δ = -1023
Delta is less than zero, so there is no solution for the equation

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