(8y+2)*(9y+3)=6

Solution for (8y+2)*(9y+3)=6 equation:

(8y+2)(9y+3)=6

We move all terms to the left:

(8y+2)(9y+3)-(6)=0

We multiply parentheses ..

(+72y^2+24y+18y+6)-6=0

We get rid of parentheses

72y^2+24y+18y+6-6=0

We add all the numbers together, and all the variables

72y^2+42y=0

a = 72; b = 42; c = 0;
Δ = b2-4ac
Δ = 422-4·72·0
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-42}{2*72}=\frac{-84}{144}
=-7/12
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+42}{2*72}=\frac{0}{144}
=0
$