(8y+1)=(6y+5)

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Solution for (8y+1)=(6y+5) equation: 



(8y+1)=(6y+5)

We move all terms to the left:

(8y+1)-((6y+5))=0

We get rid of parentheses

8y-((6y+5))+1=0



We calculate terms in parentheses: -((6y+5)), so:

(6y+5)

We get rid of parentheses

6y+5

Back to the equation:

-(6y+5)



We get rid of parentheses

8y-6y-5+1=0

We add all the numbers together, and all the variables

2y-4=0

We move all terms containing y to the left, all other terms to the right

2y=4

y=4/2

y=2

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