(8x-8)(4x+3)=0

Solution for (8x-8)(4x+3)=0 equation:

(8x-8)(4x+3)=0

We multiply parentheses ..

(+32x^2+24x-32x-24)=0

We get rid of parentheses

32x^2+24x-32x-24=0

We add all the numbers together, and all the variables

32x^2-8x-24=0

a = 32; b = -8; c = -24;
Δ = b2-4ac
Δ = -82-4·32·(-24)
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-56}{2*32}=\frac{-48}{64}
=-3/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+56}{2*32}=\frac{64}{64}
=1
$