(8x-8)(2x+6)=0

Solution for (8x-8)(2x+6)=0 equation:

(8x-8)(2x+6)=0

We multiply parentheses ..

(+16x^2+48x-16x-48)=0

We get rid of parentheses

16x^2+48x-16x-48=0

We add all the numbers together, and all the variables

16x^2+32x-48=0

a = 16; b = 32; c = -48;
Δ = b2-4ac
Δ = 322-4·16·(-48)
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-64}{2*16}=\frac{-96}{32}
=-3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+64}{2*16}=\frac{32}{32}
=1
$