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(8x-6)=(5x+6)
We move all terms to the left:
(8x-6)-((5x+6))=0
We get rid of parentheses
8x-((5x+6))-6=0
We calculate terms in parentheses: -((5x+6)), so:We get rid of parentheses
(5x+6)
We get rid of parentheses
5x+6
Back to the equation:
-(5x+6)
8x-5x-6-6=0
We add all the numbers together, and all the variables
3x-12=0
We move all terms containing x to the left, all other terms to the right
3x=12
x=12/3
x=4
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