(8x-5)+(2x)=(3x-10)

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Solution for (8x-5)+(2x)=(3x-10) equation: 



(8x-5)+(2x)=(3x-10)

We move all terms to the left:

(8x-5)+(2x)-((3x-10))=0

We add all the numbers together, and all the variables

2x+(8x-5)-((3x-10))=0

We get rid of parentheses

2x+8x-((3x-10))-5=0



We calculate terms in parentheses: -((3x-10)), so:

(3x-10)

We get rid of parentheses

3x-10

Back to the equation:

-(3x-10)



We add all the numbers together, and all the variables

10x-(3x-10)-5=0

We get rid of parentheses

10x-3x+10-5=0

We add all the numbers together, and all the variables

7x+5=0

We move all terms containing x to the left, all other terms to the right

7x=-5

x=-5/7

x=-5/7

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