(8x-41)=(4x+35)

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Solution for (8x-41)=(4x+35) equation: 



(8x-41)=(4x+35)

We move all terms to the left:

(8x-41)-((4x+35))=0

We get rid of parentheses

8x-((4x+35))-41=0



We calculate terms in parentheses: -((4x+35)), so:

(4x+35)

We get rid of parentheses

4x+35

Back to the equation:

-(4x+35)



We get rid of parentheses

8x-4x-35-41=0

We add all the numbers together, and all the variables

4x-76=0

We move all terms containing x to the left, all other terms to the right

4x=76

x=76/4

x=19

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