(8x-4)=(6x+12)

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Solution for (8x-4)=(6x+12) equation: 



(8x-4)=(6x+12)

We move all terms to the left:

(8x-4)-((6x+12))=0

We get rid of parentheses

8x-((6x+12))-4=0



We calculate terms in parentheses: -((6x+12)), so:

(6x+12)

We get rid of parentheses

6x+12

Back to the equation:

-(6x+12)



We get rid of parentheses

8x-6x-12-4=0

We add all the numbers together, and all the variables

2x-16=0

We move all terms containing x to the left, all other terms to the right

2x=16

x=16/2

x=8

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