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(8x-4)=(2x+54)
We move all terms to the left:
(8x-4)-((2x+54))=0
We get rid of parentheses
8x-((2x+54))-4=0
We calculate terms in parentheses: -((2x+54)), so:We get rid of parentheses
(2x+54)
We get rid of parentheses
2x+54
Back to the equation:
-(2x+54)
8x-2x-54-4=0
We add all the numbers together, and all the variables
6x-58=0
We move all terms containing x to the left, all other terms to the right
6x=58
x=58/6
x=9+2/3
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