(8x-4)+(3x+17)=(17x-23)

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Solution for (8x-4)+(3x+17)=(17x-23) equation: 



(8x-4)+(3x+17)=(17x-23)

We move all terms to the left:

(8x-4)+(3x+17)-((17x-23))=0

We get rid of parentheses

8x+3x-((17x-23))-4+17=0



We calculate terms in parentheses: -((17x-23)), so:

(17x-23)

We get rid of parentheses

17x-23

Back to the equation:

-(17x-23)



We add all the numbers together, and all the variables

11x-(17x-23)+13=0

We get rid of parentheses

11x-17x+23+13=0

We add all the numbers together, and all the variables

-6x+36=0

We move all terms containing x to the left, all other terms to the right

-6x=-36

x=-36/-6

x=+6

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