(8x-4)(7x+6)=0

Solution for (8x-4)(7x+6)=0 equation:

(8x-4)(7x+6)=0

We multiply parentheses ..

(+56x^2+48x-28x-24)=0

We get rid of parentheses

56x^2+48x-28x-24=0

We add all the numbers together, and all the variables

56x^2+20x-24=0

a = 56; b = 20; c = -24;
Δ = b2-4ac
Δ = 202-4·56·(-24)
Δ = 5776
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5776}=76$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-76}{2*56}=\frac{-96}{112}
=-6/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+76}{2*56}=\frac{56}{112}
=1/2
$