(8x-3)(9x+3)=0

Solution for (8x-3)(9x+3)=0 equation:

(8x-3)(9x+3)=0

We multiply parentheses ..

(+72x^2+24x-27x-9)=0

We get rid of parentheses

72x^2+24x-27x-9=0

We add all the numbers together, and all the variables

72x^2-3x-9=0

a = 72; b = -3; c = -9;
Δ = b2-4ac
Δ = -32-4·72·(-9)
Δ = 2601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2601}=51$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-51}{2*72}=\frac{-48}{144}
=-1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+51}{2*72}=\frac{54}{144}
=3/8
$