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(8x-3)(3x+3)=0
We multiply parentheses ..
(+24x^2+24x-9x-9)=0
We get rid of parentheses
24x^2+24x-9x-9=0
We add all the numbers together, and all the variables
24x^2+15x-9=0
a = 24; b = 15; c = -9;
Δ = b2-4ac
Δ = 152-4·24·(-9)
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1089}=33$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-33}{2*24}=\frac{-48}{48} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+33}{2*24}=\frac{18}{48} =3/8 $
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