(8x-28-2x=-10)*

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Solution for (8x-28-2x=-10)* equation: 



(8x-28-2x=-10)*

We move all terms to the left:

(8x-28-2x-(-10)*)=0



We calculate terms in parentheses: +(8x-28-2x-(-10)*), so:

8x-28-2x-(-10)*

determiningTheFunctionDomain
8x-2x-28-(-10)*

We add all the numbers together, and all the variables

6x

Back to the equation:

+(6x)



x=0/6

x=0

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