(8x-27)=(4x+33)

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Solution for (8x-27)=(4x+33) equation: 



(8x-27)=(4x+33)

We move all terms to the left:

(8x-27)-((4x+33))=0

We get rid of parentheses

8x-((4x+33))-27=0



We calculate terms in parentheses: -((4x+33)), so:

(4x+33)

We get rid of parentheses

4x+33

Back to the equation:

-(4x+33)



We get rid of parentheses

8x-4x-33-27=0

We add all the numbers together, and all the variables

4x-60=0

We move all terms containing x to the left, all other terms to the right

4x=60

x=60/4

x=15

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