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(8x-2)(10x+15)=0
We multiply parentheses ..
(+80x^2+120x-20x-30)=0
We get rid of parentheses
80x^2+120x-20x-30=0
We add all the numbers together, and all the variables
80x^2+100x-30=0
a = 80; b = 100; c = -30;
Δ = b2-4ac
Δ = 1002-4·80·(-30)
Δ = 19600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{19600}=140$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-140}{2*80}=\frac{-240}{160} =-1+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+140}{2*80}=\frac{40}{160} =1/4 $
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