(8x-18)=(2x+5)+(2x+5)

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Solution for (8x-18)=(2x+5)+(2x+5) equation: 



(8x-18)=(2x+5)+(2x+5)

We move all terms to the left:

(8x-18)-((2x+5)+(2x+5))=0

We get rid of parentheses

8x-((2x+5)+(2x+5))-18=0



We calculate terms in parentheses: -((2x+5)+(2x+5)), so:

(2x+5)+(2x+5)

We get rid of parentheses

2x+2x+5+5

We add all the numbers together, and all the variables

4x+10

Back to the equation:

-(4x+10)



We get rid of parentheses

8x-4x-10-18=0

We add all the numbers together, and all the variables

4x-28=0

We move all terms containing x to the left, all other terms to the right

4x=28

x=28/4

x=7

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