(8x-18)+4(x+4)-2(x+7)=40

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Solution for (8x-18)+4(x+4)-2(x+7)=40 equation: 



(8x-18)+4(x+4)-2(x+7)=40

We move all terms to the left:

(8x-18)+4(x+4)-2(x+7)-(40)=0

We multiply parentheses

(8x-18)+4x-2x+16-14-40=0

We get rid of parentheses

8x+4x-2x-18+16-14-40=0

We add all the numbers together, and all the variables

10x-56=0

We move all terms containing x to the left, all other terms to the right

10x=56

x=56/10

x=5+3/5

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