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(8x-15)=(3x+15)
We move all terms to the left:
(8x-15)-((3x+15))=0
We get rid of parentheses
8x-((3x+15))-15=0
We calculate terms in parentheses: -((3x+15)), so:We get rid of parentheses
(3x+15)
We get rid of parentheses
3x+15
Back to the equation:
-(3x+15)
8x-3x-15-15=0
We add all the numbers together, and all the variables
5x-30=0
We move all terms containing x to the left, all other terms to the right
5x=30
x=30/5
x=6
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