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(8x-12)/(x)-(7x-3)/(2x)=5-(8x+12)/(3x)
We move all terms to the left:
(8x-12)/(x)-(7x-3)/(2x)-(5-(8x+12)/(3x))=0
Domain of the equation: x!=0
x∈R
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 3x)!=0We calculate fractions
x!=0/1
x!=0
x∈R
We do not support expression: x^3
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