(8x-10)=(6x+20)

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Solution for (8x-10)=(6x+20) equation: 



(8x-10)=(6x+20)

We move all terms to the left:

(8x-10)-((6x+20))=0

We get rid of parentheses

8x-((6x+20))-10=0



We calculate terms in parentheses: -((6x+20)), so:

(6x+20)

We get rid of parentheses

6x+20

Back to the equation:

-(6x+20)



We get rid of parentheses

8x-6x-20-10=0

We add all the numbers together, and all the variables

2x-30=0

We move all terms containing x to the left, all other terms to the right

2x=30

x=30/2

x=15

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